Exploring Analyic Geometry with Mathematica® |
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Shoulder Point on Median
camedian.html
Exploration
Let C be a conic arc with control points
,
and
and projective discriminant ρ. Let P be the point on the median
associated with vertex
of
such that
(
is the midpoint of
). Show that P is coincident with the shoulder point of C, having coordinates
.
Approach
Construct the geometry and compare the coordinates of P to the shoulder point coordinates.
Initialize
To initialize Descarta2D, select the input cell bracket and press SHIFT-Enter.
This initialization assumes that the Descarta2D software has been copied into one of the standard directories for AddOns which are on the Mathematica search path, $Path.
<<Descarta2D`
Solution
Create the conic arc control points.
Clear[x0,y0,xA,yA,x1,y1];
p0=Point2D[P0={x0,y0}];
pA=Point2D[PA={xA,yA}];
p1=Point2D[P1={x1,y1}];
Construct the midpoint of the chord.
pM=Point2D[p0,p1]
Construct the point on the median.
Clear[p];
P=Point2D[pM,pA,p*Distance2D[pM,pA]] //Simplify
Construct the shoulder point.
Clear[xM,yM];
Q=Point2D[{
xM + p (xA - xM) /. xM->(x0+x1)/2,
yM + p (yA - yM) /. yM->(y0+y1)/2}] //Simplify
The point on the median is coincident with the shoulder point.
IsCoincident2D[P,Q]
Discussion
This is a plot of a numerical example.
ca1=ConicArc2D[P0,PA,P1,p];
Sketch2D[{ca1,p0,pA,p1,pM,Q,
Segment2D[pM,pA]} //. {
x0->0, y0->0, xA->2, yA->6, x1->6, y1->0, p->0.65},
PlotRange->All]
Graphics saved as "camedi01.eps".