Exploring Analyic Geometry with Mathematica® |
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Circle–Point Midpoint Theorem
cirptmid.html
Exploration
Graphics saved as "cir16.eps".
Show that the locus of midpoints from a fixed point
to a circle
of radius
, is a circle of radius
. Furthermore, show that the center point of the locus is the midpoint of the segment between
and the center of
.
Approach
Without loss of generality, choose the point
to be the origin and the circle
to have center
. Construct the locus of midpoints and examine its form.
Initialize
To initialize Descarta2D, select the input cell bracket and press SHIFT-Enter.
This initialization assumes that the Descarta2D software has been copied into one of the standard directories for AddOns which are on the Mathematica search path, $Path.
<<Descarta2D`
Solution
Construct the circle and the locus of points.
Clear[h1,r1,t];
C1=Circle2D[{h1,0},r1];
pts=Point2D[Point2D[0,0],Point2D[C1[t]]]
This locus is clearly a circle of radius
centered at
, which is the midpoint of the line segment from the point to the circle's center.
Discussion
Here's a function that computes the midpoint circle in the special position.
Circle2D[Circle2D[{h_,0},r_]]:=
Circle2D[{h/2,0},r/2];
The first plot is a numerical example with the origin outside the circle (
), while the second plot's origin is inside the circle (
).
Map[(p0=Point2D[0,0];
p1=Point2D[C1[Pi/6]];
l1=Segment2D[p0,Point2D[C1[Pi/6]]];
C2=Circle2D[C1];
P=Point2D[p0,p1];
Print[Sketch2D[{C1,C2,p0,p1,l1,P} /. #]])&,
{{h1->2,r1->1}, {h1->2,r1->3}}];
Graphics saved as "cirptm01.eps".
Graphics saved as "cirptm02.eps".